[AR] Re: Closing the loop on rocket engines

  • From: Robert Steinke <robert.steinke@xxxxxxxxx>
  • To: arocket@xxxxxxxxxxxxx
  • Date: Fri, 11 Dec 2015 12:18:07 -0700

I think what David might be getting at with the weight is that the dragster
itself is effectively an inertial dyno for the engine. If the dragster
weighs 2230 lbs (underestimate ignoring driver and fuel) = 1011 kg, and
accelerates from a standing stop to 330 miles per hour = 148 m/s in 3.7
seconds then the engine added

1/2*m*v^2 = 11 MJ of energy

11MJ / 3.7 seconds = 3MW = 4000 hp

That's an underestimate ignoring some of the mass and any friction or
slippage, but is it enough of an underestimate to account for the gap
between 4000 and 10,000 hp?


On Fri, Dec 11, 2015 at 4:36 AM, Monroe L. King Jr. <
monroe@xxxxxxxxxxxxxxxxxx> wrote:

Minimum weight (dry) is 2230 lbs. Add driver and fuel. fuel is about 23
gal 90% nitro 10% methanol.

The car would not fly if that's what you mean.

-------- Original Message --------
Subject: [AR] Re: Closing the loop on rocket engines
From: David Weinshenker <daze39@xxxxxxxxxxxxx>
Date: Thu, December 10, 2015 10:04 pm
To: arocket@xxxxxxxxxxxxx


On 12/10/2015 07:02 PM, Monroe L. King Jr. wrote:
The exhaust of a top fuel dragster put's out enough thrust to qualify
it
as a rocket engine [...] engine weighs about 500 lbs

So what's a typical total mass (engine and chassis) for such
a vehicle?

-dave w


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