[Ilugc] regular expression the check if a string is absent

From: freedomyug@xxxxxxxxx (Gourav Shah)
Date: Mon Jun 8 19:15:07 2009

I am trying to build a regular expression that will find all strings that
do
not start with '2009/'. Any clues?

I am assuming you could use grep here, if not, please specify how you intend
to do the pattern matching.

grep has a option to invert match, here is a snip from manpage,
...

       -v, --invert-match
              Invert the sense of matching, to select non-matching lines.
(-v is specified by POSIX.)

so if its grep, you could use,  grep "^2009/"  <FILENAME>

e.g.

$ cat >> /tmp/t.txt
snfgd
fdnbfognbof errgirnbinr
kjfnfbjgnb 434fgv 54y 5obn
2009/ rgerigbir nr
vrgnbn
2009/ y fdgovrf23 3gp 4
bgfbog
232234
565
2009
regtrgm ^[[A^[[A
2009 enfvfrnv evirvir
vornbtr

$ grep "^2009/" /tmp/t.txt
2009/ rgerigbir nr
2009/ y fdgovrf23 3gp 4

$ grep -v "^2009/" /tmp/t.txt
snfgd
fdnbfognbof errgirnbinr
kjfnfbjgnb 434fgv 54y 5obn
vrgnbn
bgfbog
232234
565
2009 enfvfrnv evirvir
vornbtr

Thanks
Gourav

References:
- [Ilugc] regular expression the check if a string is absent
  - From: Kenneth Gonsalves

[Ilugc] regular expression the check if a string is absent

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