[jawsscripts] Re: Query on Doug's bx Toolbox?
- From: Doug Lee <doug.lee@xxxxxxxxxxxxxxxx>
- To: jawsscripts@xxxxxxxxxxxxx
- Date: Fri, 23 Jul 2010 07:46:20 -0400
There are ways to do this, but I think there's a larger problem: In
many applications, there's no guarantee that the window tree at one
instant will be the same at another instant. A window will not change
class, but windows can be added to and removed from the tree at
various times, or the tree can be built differently or sorted
differently based on various factors.
As for how to do it though, the EnumerateChildWindows idea would work.
You don't really need to sort the windowclasses though, because I
think you're just looking for duplicates of one class at a time. Just
use your callback function to check each window's class against the
one you're looking for. If you want to write a function to check for
this and just return a count of class duplicates, use a global
variable for the count, clear it in your main function, increment it
when appropriate in your callback function, then return it from your
main one.
On Fri, Jul 23, 2010 at 07:36:56AM -0400, Homme, James wrote:
Hi Geoff,
The only way I can think of right now is to get the handle for the application
main window, and loop through every window with enumerate child windows and
check to see if a class repeats. This is untested, but maybe it would work.
Make a global array of strings. write a call back function that simply adds the
class of the handle of the window that enumerate child windows passes to it.
When enumerate child windows is done, your global string array will contain the
classes of all the windows in the application. Unfortunately I don't see
anything that sorts an array, then you could use string compare to point at two
indexes and compare them to see if the values they point to are equal. But I
guess you could point at the first element of the array and then loop through
the second through the last and see if any of those classes equal the first. If
not, point to the second index and loop starting with the third. Then loop
starting with the third pointing to the fourth. And each ti
me you look through classes, the loop would be shorter. And finally, you'd
either find two classes that are equal, or you'd be finished looping.
Jim
Jim Homme,
Usability Services,
Phone: 412-544-1810. Skype: jim.homme
Internal recipients, Read my accessibility blog. Discuss accessibility here.
Accessibility Wiki: Breaking news and accessibility advice
-----Original Message-----
From: jawsscripts-bounce@xxxxxxxxxxxxx
[mailto:jawsscripts-bounce@xxxxxxxxxxxxx] On Behalf Of Geoff Chapman
Sent: Friday, July 23, 2010 1:23 AM
To: jawsscripts@xxxxxxxxxxxxx
Subject: [jawsscripts] Queery on Doug's bx ToolBox?
Scripters, can anyone tell me if there is a way, either without, or with,
doug's Bx ToolBox installed, of asking the application quickly and easily,
if any other windows, have a particular class?
i.e. if a window doesn't have a name, that is, it's blank, and I wana use
findWindow to locate it uniquely, and so I'm restricted to class as the only
uniquely identifying attribute of the window being searched for,
I just thought it'd be rather handy for me to easily be able to find out, if
any other visible/non-disabled windows in the application, or even perhaps any
of them, might have the same class? such that I might predetermine whether
searching for a window with a given className only, might fail in unforseen
circumstances?
thanks for any thoughts.
Geoff c.
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Doug Lee, Senior Accessibility Programmer
SSB BART Group - Accessibility-on-Demand
mailto:doug.lee@xxxxxxxxxxxxxxxx http://www.ssbbartgroup.com
"While they were saying among themselves it cannot be done,
it was done." --Helen Keller
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