If pos = stringContains(s, someString) and lSomeString = stringLength(someString), SomeString's ending position in S will be pos + lSomeString - 1. On Tue, 20 Jul 2010 03:29:52 +1000, Geoff Chapman wrote: > Mighty Scripters. > In wanting to first isolate and reprocess the textual, and also numeric > Caller ID Numeric components, of a mixed line containing firstly a 3 digit > number, that's ok as this is constant, then a couple of words that I need to > isolate, , then sometimes, not always though, a bunch of numbers as a Caller > ID at the end of these lines, with nothing but what jaws speaks as, Blank, or > character 0 if you queery it, between these 3 separate components as known > delimiters, > well, A much more advanced scripter friend of mine pulled me out of trouble > bybuilding a little function of his own which annilizes whether a given > string contains numeric components or not. And I hope to test this tomorrow, > now that I've finally formed up all the processing around text it needs to > look for in the Text String status component section, of these lines. > etc. > > However, it occurred to me, to wanna ask, well, > you know how the StringContains BuiltIn, > returns the starting position in a given string, where the second parameter > string your searching for, starts to match, > well, I wondered, whether any fancy dude up here, may've ever divined some > magic code/way, of, say, building something which could return the number of > the ending position of such a string as well? > > Would not others find this a handy feature to have sometimes? > > I just wondered eh. > > Thanks for any thoughts. > > geoff c. > > > > __________� > > View the list's information and change your settings at > http://www.freelists.org/list/jawsscripts __________� View the list's information and change your settings at http://www.freelists.org/list/jawsscripts